Multiplication Using Multiplication

(Urdhva Tiryagbhyaam)

Consider the following example :

            37 * 33

Step 1 : Write it as follows

                    37

                    33

Step 2 : Multiply the left most column vertically and  write it below.

             Multiply 3 * 3 to get 9

                    37

                    33

                    9

Step 3 : Next multiply diagonally and add

            i.e. (3*3) + (3*7) = 9 + 21 = 30

Since 30 is a 2 digit number put the last digit (here '0' ) next to 9 and the other digits (here '3' ) below 9

                    37

                    33

                    90

                    3

Step 4 :  Now multiply the RHS column and put it below and total to get the Answer.

                    37

                    33

                    901

                    32 

                   1221

  Hence 1221 is the Answer

---

This method can be extended for any number of digits .....following are the various steps:-

Error while starting Tomcat Server version x?SOLVED!!!!

Sometimes following error is encountered while starting Apache Tomcat Server which can be resolved very easily :

ERROR

"Windows could not start the Apache Tomcat 6 on Local Computer. For more information, review the System Event Log. If this is a non-Microsoft service, contact the service vendor, and refer to service-specific error code 0"

In place of "error code 0" it can be any error code "x"

Solution

When an error of this sort come. please go to start -> configure tomcat -> startup -> Mode -> java similarly start -> configure tomcat -> shutdown -> Mode -> java

[Fix] Windows 7 is not Genuine Error Message, Make It Original and Activated Again

Its a common problem which lots of Windows 7 users face. We have received many emails about this problem, so today we are sharing a working solution for it. In fact many Windows 7 SP1 RC users are also facing this problem.

Problem Symptom:

You were using genuine Windows 7 without any problem. It was activated properly. But one day when you logged into Windows, you received following message:

Windows is not genuine
Your computer might not be running a counterfeit copy of Windows.

Along with the above mentioned message, you also noticed that the desktop background became black and following error message was shown on the bottom right corner of the screen:

This copy of Windows is not genuine.

Also when you checked System Properties, you got following error message:

You must activate today. Activate Windows now.

Problem Cause:

Actually this problem occurs when there is a lack of permissions on a registry key "HKEY_USERS\S-1-5-20". By default, System, Network Service and Administrator accounts have "Full Control" and "Read" permissions on this registry key. But sometimes "Network Service" doesn't have proper permissions on this registry key and you face this problem. This may be the result of applying a Plug and Play Group Policy object (GPO). The Licensing service uses Plug and Play to obtain your system hardware ID information and binds the license to the computer. By default, it doesn't have proper permissions to access Plug and Play service.

Problem Solution:

There are 2 solutions actually. You can try them one by one:

METHOD 1: Using RSOP

1. Open Command Prompt as Administrator as mentioned here and then type rsop.msc and press Enter. It'll open RSOP (Resultant Set Of Policy) window.

2. Now go to:

Computer Configuration/Windows Settings/Security Settings/System Services

3. In right-side pane, check "Startup" type of "Plug and Play" service. It should be set to "Not Defined". If its not, double-click on it and set its Startup type to "Automatic".

4. Now provide following command in RUN or Command Prompt:

gpupdate /force

5. That's it. Restart your system and your problem should be fixed.

METHOD 2: Using Registry Editor

1. Type regedit in RUN or Start Menu search box and press Enter. It'll open Registry Editor.

2. Now go to following key:

HKEY_USERS\S-1-5-20

3. Right-click on "S-1-5-20" key and select "Permissions...". It'll open a new window.

4. Select "NETWORK SERVICE" in user list and check "Allow" box given for "Full Control" permission. Click on OK button to apply the changes.

NOTE: If "NETWORK SERVICE" is not present in user list, click on "Add" button. Now typeNetwork Service in "Enter the object names to select type" and click on "Check Names" button. It'll detect and confirm the username. Click on OK button.

5. That's it. Restart your system and your problem should be fixed.

                                                  METHOD 3: Using Command Prompt                                         

Step.1  Go to Start menu and search for cmd , you will get cmd.exe in search result here do a Right Click on cmd.exe and click on Run as Administrator, and you will get Command Prompt.

Step 2. Once the command prompt is opened now type the following command, SLMGR -REARM , make sure you type the same command without any mistake, and also ensure that command prompt is opened in administrator mode otherwise it will not work.

 

Step 3. Once you typed the above command in command prompt window then hit Enter button on your keyboard to execute the above command.

Step 4. After you hit enter a confirmation window will appear with the details of command execution as.

Step 5. Now  Restart your computer you will not get that error again like Windows 7 build 7600/7601 This copy of windows is not genuine.

- See more at: http://www.itechfever.com/how-to-fix-windows-7-not-genuine-error/#sthash.cKRNxdYE.dpuf

Typing on a Slide During the Presentation - Office 2007

This module explains how to prepare a PowerPoint show to accept information typed onto the slide during the slide presentation. 

1. In this process uses items on a tab not displayed on the ribbon by default. Before continuing we must add that ribbon. Click on the Office button and slide down to the bottom right of the window that opens and then click on PowerPoint Options.
2. When the PowerPoint Options window opens, click into the box to the right of Show Developer tab in the Ribbon and then click on the OK button in the bottom right part of the window.
3. A new tab, Developer , is now on your ribbon. Click on the Developer tab to see the  options available there.
4.         
5. Click on the Text Box (ActiveX Control) button. The mouse cursor turns into a crosshair, which is a drawing tool. Click and drag diagonally to draw a text box large enough to type into.
6. For this drawing, four text boxes will be needed. The easiest way to do that is to duplicate the text box three times. With the Text Box selected, there are eight white circles around the box when it is selected, press and hold the Ctrl key while you tap the D key three times. That action is like Copy and Paste in one step.
7. Don't try to copy and paste the boxes exactly where you want them. PowerPoint will put them wherever it wants to (" You're a mean one. Mr. Gates "). When you duplicate the text box, each new box will be placed slightly down and to the right of the previous box. After you have the number of boxes you need, click and drag them to the place where you want them on the slide.
8. 
9. The default font selection will probably be too small to see easily if you project the computer to a screen. Many properties of a text box can be changed. Yo do so, right-click (or control + click on a Macintosh) the text box and select properties.
10. From the long list of properties available, select Font. When you select ("click-on") the font line a control box appears at the right end of the font line. In the image below I drew a red box around it, but you will not see a red box in PowerPoint. Clicking on the control box brings up a font change menu that will probably look familiar to you. Experiment with font size until you find one suited to your class and the size of your text boxes.

Start your show by pressing the F5 key. 

How to type infinity symbol on keyboard?

Infinity symbol text typing on keyboard.

Platform	Key type	Description
PC windows	Alt+236	Hold the ALT key and type 236 on the num-lock keypad.
Macintosh	Option+5	Hold the Option key and press 5
Microsoft word	Insert > Symbol > ∞	Menu selection: Insert > Symbol > ∞
	Alt+236	Hold the ALT key and type 236 on the num-lock keypad.
Microsoft excel	Insert > Symbol > ∞	Menu selection: Insert > Symbol > ∞
	Alt+236	Hold the ALT key and type 236 on the num-lock keypad.
Web page	Ctrl+C, Ctrl+V	Copy ∞ from here and paste it in your web page.
Facebook	Ctrl+C, Ctrl+V	Copy ∞ from here and paste it in your Facebook page.
HTML	∞ or ∞
ASCII code	236
Unicode	U+221E
LaTeX	\infty
MATLAB	\infty	Example: title('Graph to \infty')

How to run a NetBeans project in command prompt?

You cannot run a file compiled using NetBeans because :

• while creating new file in netbeans we always first make a new project which automatically creates a  new package
• the package which is created is automatically added at the top of each of the file made using netbeans eg:

  Package javaapplication3; /**  *  * @author Rajeev Handa  */ public class JavaApplication3 {     /**      * @param args the command line arguments      */     public static void main(String[] args) {         // TODO code application logic here         int i=10;         System.out.println(i);     }   }

  In this case the default package made in netbeans is 'javaapplicatiion3'
• so to run a program in cmd prompt first of all:

1. Copy the [abc].java file into the bin folder of jdk 
2. Open the file and edit it with notepad
3. remove the name of the package i.e. Package javaapplication3
4. Then press Ctrl+S
5. Open cmd Prompt
6. Go to the bin folder or locate it by typing [cd..] command eg:cd java [enter] cd  jdk[enter] cd bin[enter]
7. Type javac [name_of_file].java
8. You will see that a class file gets created in bin folder
9. Then type java [name_of_class] 
10. Thats it...

What does “Could not find or load main class” mean?

First of all, you need to understand the correct way to launch a program using the java (or javaw) command.

The normal syntax¹ is this:

    java [ <option> ... ] <class-name> [<argument> ...]

where  is a command line option (starting with a "-" character),  is a fully qualified Java class name, and  is an arbitrary command line argument that gets passed to your application.

^{1 - There is a second syntax for "executable" JAR files which I will describe at the bottom.}

For example:

    java -Xmx100m com.acme.example.ListUser fred

What this is going to do is the following:

1. Search for the compiled version of the com.acme.example.ListUser class.
2. Load the class.
3. Check that the class has a main method with signature static void main(String[]).
4. Call that method passing it the command line arguments as a String[].

Reasons why Java cannot find the class

When you get the message "Could not find or load main class ...", that means that the first step has failed. The java command was not able to find the class. And indeed, the "..." in the message will be the fully qualified class name that java is looking for.

So why might it be unable to find the class? Basically, there are two main causes:

The first likely cause is that you may have provided the wrong class name. (Or ... the right class name, but in the wrong form.) Considering the example above, here a variety of wrong ways to specify the class name:

• Example #1 - a simple class name:

  java ListUser

  When the class is declared in a package such as com.acme.example, then you must use the full classname including the package name in the java command; e.g.

  java com.acme.example.ListUser

• Example #2 - a filename or pathname rather than a class name:

  java ListUser.class
  java com/acme/example/ListUser.class

• Example #3 - a class name with the casing incorrect:

  java com.acme.example.listuser

• Example #4 - a typo

  java com.acme.example.mistuser

The second likely cause is that the class name is correct, but that the java command cannot find the class. To understand this, you need to understand the concept of the "classpath". This is explainedwell by the Oracle documentation:

• The java command documentation
• Setting the Classpath.
• The Java Tutorial - PATH and CLASSPATH

So ... if you have specified the class name correctly, the next thing to check is that you have specified the classpath correctly:

1. Read the three documents linked above. (Yes ... READ them.)
2. Look at command line and / or the CLASSPATH environment variable that is in effect when you run the java command. Check that the directory names and JAR file names are correct.
3. If there are relative pathnames in the classpath, check that they resolve correctly ... from the current directory that is in effect when you run the java command.
4. Check that the class (mentioned in the error message) can be located on the effective classpath.

Additional Notes:

1. When you put a directory on the classpath, it notionally corresponds to the root of the qualified name space. Classes are located in the directory structure beneath that root, by mapping the fully qualified name to a pathname. So for example, if "/usr/local/acme/classes" is on the class path, then when the JVM looks for a class called com.acme.example.Foon, it will look for a ".class" file with this pathname:

       /usr/local/acme/classes/com/acme/example/Foon.class

   If you had put "/usr/local/acme/classes/com/acme/example" on the classpath, then the JVM wouldn't be able to find the class.
2. The classpath needs to include all of the other (non-system) classes that your application depends on. (The system classes are located automatically, and you rarely need to concern yourself with this.)

The java -jar  syntax

The alternative syntax used for "executable" JAR files is as follows:

    java [ <option> ... ] -jar <jar-file-name> [<argument> ...]

e.g.

    java -Xmx100m -jar /usr/local/acme-example/listuser.jar fred

In this case the name of the entry-point class (i.e. com.acme.example.ListUser) and the classpath are specified in the MANIFEST of the JAR file.

IDEs

A typical Java IDE has support for running Java applications in the IDE JVM itself or in a child JVM. These are generally immune from this particular exception, because the IDE uses its own mechanisms to construct the runtime classpath, identify the main class and create the javacommand line.

However it is still possible for this exception to occur, if you do things behind the back of the IDE to break things. For example, if you have previously set up an Application Launcher for your Java app in Eclipse, and you then moved the JAR file containing the "main" class to a different place in the file system without telling Eclipse, Eclipse would unwittingly launch the JVM with an incorrect classpath.

In short, if you get this problem in an IDE, check for things like stale IDE state and broken project references or launcher configurations.